Q27 / 160 · WBJEE 2015 · Chemistry
The reaction of methyltrichloroacetate $\left(\mathrm{Cl}_{3} \mathrm{CCO}_{2} \mathrm{Me}\right)$ with sodium methoxide $\mathrm({NaOMe})$ generates
- Acarbocation
- Correct answerBcarbene
- Ccarbanion
- Dcarbon radical
Hence, the correct answer is option: 'B'.