Among the following carbocations : (I) \(\mathrm{Ph}_{2}\stackrel{+}{\mathrm{C}} \mathrm{CH}_{2} \mathrm{Me}(\mathrm{II}) \mathrm{Ph} \mathrm{CH}_{2} \mathrm{CH}_{2} \stackrel{+}{\mathrm{C}} \mathrm{HPh}\) (III) \(\mathrm{Ph}_{2} \mathrm{CH} \stackrel{+}{\mathrm{C}} \mathrm{HMe}\) (IV) \(\mathrm{Ph}_{2} \mathrm{C}(\mathrm{Me}) \stackrel{+}{\mathrm{C}} H_{2}\) the order of stability is :

• A

  IV $>\mathrm{II}>\mathrm{I}>\mathrm{III}$
• Correct answer
  B

  $I>\mathrm{II}>\mathrm{III}>\mathrm{IV}$
• C

  II $>I>\mathrm{IV}>\mathrm{III}$
• D

  $\mathrm{I}>\mathrm{TV}>\mathrm{III}>\mathrm{II}$

Solution

The order of stability of carbocation is $3^{\circ}$ benzylic $>2^{\circ}$ benzylic $>2^{*}>1^{*}$ Thus, the correct order of stability will be

Hence, the correct answer is option: 'B'.