Q111 / 200 · NEET 2008 (Screening) · Physics

The ratio of the radii of gyration of a circular disc to that of a circular ring, each of same mass and radius, around their respective axes is

  • A
    $\sqrt{3}: \sqrt{2}$
  • Correct answer
    B
    $1: \sqrt{2}$
  • C
    $\sqrt{2}: 1$
  • D
    $\sqrt{2}: \sqrt{3}$

Solution

Key Idea : The square root of the ratio of the moment of inertia of a rigid body and its mass is called radius of gyration. As in key idea, radius of gyration is given by $K=\sqrt{\frac{I}{M}}$ For given problem $\frac{K_{\text {disc }}}{K_{\text {ring }}}=\sqrt{\frac{I_{\text {disc }}}{I_{\text {ring }}}}$ But $I_{\text {disc }}$ (about its axis) $=\frac{1}{2} M R^2$ and $I_{\text {ring }}$ (about its axis) $=M R^2$ where $R$ is the radius of both bodies. Therefore, Eq. (i) becomes $\frac{K_{\mathrm{disc}}}{K_{\text {ring }}}=\sqrt{\frac{\frac{1}{2} M R^2}{M R^2}}=1: \sqrt{2}$

Hence, the correct answer is option: 'B'.

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