Q88 / 90 · JEE Main 2024 (30 Jan Shift 1) · Physics

The ratio of the magnitude of the kinetic energy to the potential energy of an electron in the $5^{th}$ excited state of a hydrogen atom is :

A
$4$
B
$\frac{1}{4}$
Correct answer
C
$\frac{1}{2}$
D
$1$

Solution

As we know, $K E = \frac{1}{2} | P E |$ for any orbit.

$∴ \frac{K E}{| P E |} = \frac{1}{2}$

Hence, the correct answer is option: 'C'.

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