The ratio of the dimensions of Planck’s constant of that of moment of inertia is the dimension of

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Correct answer: (C) Frequency. The dimensions of Planck’s constant, h=E/v=(ML^2T^(-2))/(M^0L^0T^(-1))=ML^2T^(-1) And that moment of inertia, l=MR^2=ML^2=ML^2T^0 ∴h/l=(ML^2T^(-1))/(ML^2T^0)=T^(-1)=v

The ratio of the dimensions of Planck’s constant of that of moment of inertia is the dimension of

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