Let x=π R (fracp^2-Q^22 ) , where P, Q and R are lengths. The physical quantity ' x^′ is

Correct answer: (A) volume. INTIAL LENGTH =l FINAL LENGTH=L. NET DISTANCE/LENGTH PULLED =L-l ∴ T I M E P E R I O D=2 π √((L-ℓ)/g) allo, P=(2 π)/(T .) ∴ P= g/(L-l) . ( option -3) .

Q108 / 150 · MHT CET 2020 (19 Oct Shift 2) · Physics

Let $x=\pi R\left(\frac{p^{2}-Q^{2}}{2}\right)$, where $P, Q$ and $R$ are lengths. The physical quantity ' $x^{\prime}$ is

Correct answer
A
volume
B
Area Under Curves
C
velocity
D
length

Solution

INTIAL LENGTH $=l$ FINAL LENGTH=L. NET DISTANCE/LENGTH PULLED $=L-l$ $\therefore T I M E P E R I O D=2 \pi \sqrt{\frac{L-\ell}{g}}$ allo, $P=\frac{2 \pi}{T .}$ $\begin{aligned} \therefore P=& \frac{g}{L-l} . \\ &(\text { option }-3) . \end{aligned}$

Hence, the correct answer is option: 'A'.

Let $x=\pi R\left(\frac{p^{2}-Q^{2}}{2}\right)$, where $P, Q$ and $R$ are lengths. The physical quantity ' $x^{\prime}$ is

Solution

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