The ratio of maximum acceleration to maximum velocity in a simple harmonic motion is 10 s^(-1). At, t=0 the displacement is 5 m. What is the maximum…

Question

The ratio of maximum acceleration to maximum velocity in a simple harmonic motion is 10 s^(-1). At, t=0 the displacement is 5 m. What is the maximum acceleration? The initial phase is (π)/4 .

MARKS Content Team · Accepted Answer

Correct answer: (D) 500√2 m s^(-2). In a simple harmonic motion, Maximum acceleration, f_max=ω^2A Maximum velocity, v_max=Aω. f_maxv_max=(ω^2A)/(Aω)=ω ω=10 Displacement in SHM is x=Asin⁡ωt+(π)/4 At t=0 5=Asin⁡(π)/4 A=5√2. Max acceleration = ω^2A =100×5√2 =500√(2 ) m s^(-2)

The ratio of maximum acceleration to maximum velocity in a simple harmonic motion is $10 s^{- 1} .$ At, $t = 0$ the displacement is $5 m .$ What is the maximum acceleration? The initial phase is $\frac{π}{4}$ .

Solution

Relevant Questions

The ratio of maximum acceleration to maximum velocity in a simple harmonic motion is 10 s-1. At, t=0 the displacement is 5 m. What is the maximum acceleration? The initial phase is π4 .

Solution

Relevant Questions

The ratio of maximum acceleration to maximum velocity in a simple harmonic motion is $10 s^{- 1} .$ At, $t = 0$ the displacement is $5 m .$ What is the maximum acceleration? The initial phase is $\frac{π}{4}$ .