Q7 / 90 · JEE Main 2024 (06 Apr Shift 2) · Chemistry

The ratio \(\frac{K_P}{K_C}\) for the reaction : \(\mathrm{CO}_{(\mathrm{g})}+\frac{1}{2} \mathrm{O}_{2(\mathrm{~g})} \rightleftharpoons \mathrm{CO}_{2(\mathrm{~g})}\) is :

  • Correct answer
    A
    \(\frac{1}{\sqrt{\mathrm{RT}}}\)
  • B
    \((\mathrm{RT})^{1 / 2}\)
  • C
    \(\mathrm{RT}\)
  • D
    1

Solution

$\begin{aligned} & \mathrm{CO}(\mathrm{g})+\frac{1}{2} \mathrm{O}_2(\mathrm{~g}) \rightleftharpoons \mathrm{CO}_2(\mathrm{~g}) \\ & \Delta \mathrm{n}_{\mathrm{g}}=1-\left(1+\frac{1}{2}\right)=-\frac{1}{2} \\ & \frac{\mathrm{K}_{\mathrm{p}}}{\mathrm{K}_{\mathrm{C}}}=(\mathrm{RT})^{\Delta \mathrm{n}_{\mathrm{g}}}=\frac{1}{\sqrt{\mathrm{RT}}}\end{aligned}$

Hence, the correct answer is option: 'A'.

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