Q6 / 90 · JEE Main 2024 (06 Apr Shift 2) · Chemistry
During the detection of acidic radical present in a salt, a student gets a pale yellow precipitate soluble with difficulty in \(\mathrm{NH}_4 \mathrm{OH}\) solution when sodium carbonate extract was first acidified with dil. \(\mathrm{HNO}_3\) and then \(\mathrm{AgNO}_3\) solution was added. This indicates presence of :
- Correct answerA\(\mathrm{Br}^{-}\)
- B\(\mathrm{I}^{-}\)
- C\(\mathrm{Cl}^{-}\)
- D\(\mathrm{CO}_3{ }^{2-}\)
Solution
$\begin{array}{ll}
\mathrm{Ag}^{+}+\mathrm{I}^{-} \rightarrow \mathrm{AgI} & \text{Yellow ppt.} \\
\mathrm{Ag}^{+}+\mathrm{Cl}^{-} \rightarrow \mathrm{AgCl} & \text{White ppt} \\
\mathrm{Ag}^{+}+\mathrm{Br}^{-} \rightarrow \mathrm{AgBr} & \text{Pale yellow ppt}
\end{array}$
Hence, the correct answer is option: 'A'.