The rate law for the reaction RCl+NaOH(aq)→ROH+NaCl is given by Rate =k[RCl] . The rate of the reaction will be

Question

MARKS Content Team · Accepted Answer

Correct answer: (B) Halved on reducing the concentration of alkyl halide to one half. It is a pseudo-first-order reaction (molecularity is two but of first order) as the rate of reaction does not depend upon the concentration of aqueous NaOH as it is in excess so no effect of change of concentration of it. Since r ∝ [RCl], so rate is halved when the concentration of alkyl halide is halved.

The rate law for the reaction
$R C l + N a O H (a q) \to R O H + N a C l$
is given by
Rate $= k [R C l]$ . The rate of the reaction will be

Solution

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