Q42 / 160 · TS EAMCET 2023 (12 May Shift 2) · Mathematics

The range of the function $f(x)=-\sqrt{-x^2-6 x-5}$ is

  • A
    $[0,2]$
  • Correct answer
    B
    $[-2,0]$
  • C
    $[-2,2]$
  • D
    $(-\infty, 2]$

Solution

$\begin{aligned} & -x^2-6 x-5 \\ D= & 36-4(-1)(-5)=16\end{aligned}$ Figure
$\begin{array}{ll}\therefore \quad & -x^2-6 x-5 \in(-\infty, 4] \\ \text { for } & \sqrt{-x^2-6 x-5} \\ & f(x) \in[0,2] \\ & -f(x) \in[-2,0]\end{array}$

Hence, the correct answer is option: 'B'.

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