Q42 / 160 · TS EAMCET 2023 (12 May Shift 2) · Mathematics
The range of the function $f(x)=-\sqrt{-x^2-6 x-5}$ is
- A$[0,2]$
- Correct answerB$[-2,0]$
- C$[-2,2]$
- D$(-\infty, 2]$
Solution
$\begin{aligned} & -x^2-6 x-5 \\ D= & 36-4(-1)(-5)=16\end{aligned}$

$\begin{array}{ll}\therefore \quad & -x^2-6 x-5 \in(-\infty, 4] \\ \text { for } & \sqrt{-x^2-6 x-5} \\ & f(x) \in[0,2] \\ & -f(x) \in[-2,0]\end{array}$

$\begin{array}{ll}\therefore \quad & -x^2-6 x-5 \in(-\infty, 4] \\ \text { for } & \sqrt{-x^2-6 x-5} \\ & f(x) \in[0,2] \\ & -f(x) \in[-2,0]\end{array}$
Hence, the correct answer is option: 'B'.