Q67 / 160 · TS EAMCET 2025 (04 May Shift 1) · Mathematics
If $x=\log _e 3$ then $\tanh 2 x+\operatorname{sech} 2 x=$
- A$\frac{4}{3}$
- Correct answerB$\frac{49}{41}$
- C$\frac{4}{5}$
- D$\frac{41}{49}$
Hence, the correct answer is option: 'B'.