The radius of the circle with centre at 3,2 and whose common chord with the circle C: x^2+y^2-4x-8y+16=0 is also a diameter of the circle C, is

Question

MARKS Content Team · Accepted Answer

Correct answer: (A) 3 units. Let the equation of the circle be x^2+y^2-6x-4y+c=0 So, the common chord of these 2 circles is 2x-4y+16-c=0 It passes through the centre 2,4 of the given circle, so 4-16+16-c=0⇒c=4 Hence, the radius of the circle =√(9+4-4)=3 units

The radius of the circle with centre at $(3,2)$ and whose common chord with the circle $C : x^{2} + y^{2} - 4 x - 8 y + 16 = 0$ is also a diameter of the circle $C$ , is

Solution

More Circle Questions

The radius of the circle with centre at 3,2 and whose common chord with the circle C: x2+y2-4x-8y+16=0 is also a diameter of the circle C, is

Solution

More Circle Questions

The radius of the circle with centre at $(3,2)$ and whose common chord with the circle $C : x^{2} + y^{2} - 4 x - 8 y + 16 = 0$ is also a diameter of the circle $C$ , is