Q96 / 160 · TS EAMCET 2023 (12 May Shift 2) · Mathematics
The product of the lengths of the perpendiculars drawn from the two foci of the ellipse $\frac{x^2}{9}+\frac{y^2}{25}=1$ to the tangent at any point on the ellipse is
- A$6$
- B$7$
- C$8$
- Correct answerD$9$
Solution
(1) Product of length of perpendicular from focii to a tangent of ellipse $=(\text { semi minor axis })^2$

$\therefore \quad$ For $\frac{x^2}{9}+\frac{y^2}{25}=1$ Semi minor axis $=3$ $\therefore \quad$ Product of lengths of perpendiculars $=9$.

$\therefore \quad$ For $\frac{x^2}{9}+\frac{y^2}{25}=1$ Semi minor axis $=3$ $\therefore \quad$ Product of lengths of perpendiculars $=9$.
Hence, the correct answer is option: 'D'.