Q84 / 160 · AP EAMCET 2020 (21 Sep Shift 2) · Mathematics
The population of a city grows at the annual rate of \(3 \%\). What percentage increase is expected in \(5 \mathrm{yr}\) ?
- A\(12.9 \%\)
- B\(13.9 \%\)
- C\(14.9 \%\)
- Correct answerD\(15.9 \%\)
Solution
Let the population in begining is \(P_0\), then according to the question percentage increase in 5 yr expected is
\(\begin{aligned}
\frac{P_0\left(1+\frac{3}{100}\right)^5-P_0}{P_0} \times 100 & =\left[\left(\frac{103}{100}\right)^5-1\right] \times 100 \\
& =\left[(1.03)^5-1\right] \times 100 \\
& =[1.159-1] \times 100=15.9 \%
\end{aligned}\)
Hence, option (d) is correct.
Hence, the correct answer is option: 'D'.