Q159 / 180 · KCET 2024 · Physics

The photoelectric work function for photo metal is 2.4 eV . Among the four wavelengths, the wavelength of light for which photoemission does not take place is

A
200 nm
B
300 nm
Correct answer
C
700 nm
D
400 nm

Solution

Given, $\phi_0=24 \mathrm{eV}$ We know that, $\phi_0=\frac{1240}{\lambda_0(\text { in } \mathrm{nm})}$ $\Rightarrow \quad \lambda_0($ in nm$)=\frac{1240}{\phi_0}=\frac{1240}{24}=516.6 \mathrm{~nm}$

Hence, the correct answer is option: 'C'.

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