Q66 / 90 · JEE Main 2022 (26 Jul Shift 2) · Physics

The oscillating magnetic field in a plane electromagnetic wave is given by By=5×10-6sin1000π5x-4×108t T. The amplitude of electric field will be

  • A
    15×102Vm-1
  • B
    5×10-6Vm-1
  • C
    16×1012Vm-1
  • Correct answer
    D
    4×102Vm-1

Solution

Given here, By=5×10-6sin1000π5x-4×108t T

Here, peak value of magnetic field, B0=5×10-6 T

Now the speed of the wave v=ωk=1000π×4×1081000π×5=8×107 m s-1

Using relation between magnetic and electric field, 

Peak value of electric field is E0=B0v=5×10-6×8×107=4×102 V m-1

Hence, the correct answer is option: 'D'.

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