Q56 / 160 · TS EAMCET 2018 (05 May Shift 2) · Mathematics

The number of ways of arranging 8 boys and 8 girls in a row so that boys and girls sit alternately is

A
9 !
B
$(9 !)(8 !)$
C
$(8 !)^2$
Correct answer
D
$2 !(8 !)^2$

Solution

We have, 8 boys and 8 girls. To tal number of arrangements of 8 boys and 8 girls. Sit altemately is $8 ! \times 8 ! \times 2 !=2 !(8 !)^2$

Hence, the correct answer is option: 'D'.

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