Q57 / 160 · AP EAMCET 2023 (15 May Shift 1) · Mathematics
The number of natural numbers less than 10000 which are divisible by 5 and that no digit is repeated in the same number, is
- A802
- B602
- C702
- Correct answerD1106
Solution
Natural numbers less than 10000 which are devisible by 5 , will be the numbers upto 4 digits which ends with zero or 5.
Number of all natural numbers upto 4 digits which ends with zero when no digits are repeated
$$
=(9)(8)(7)(1)+(9)(8)(1)+(9)(1)=585
$$
(Note that zero will not be counted as $0 \notin \mathbb{N}$ )
Number of all Natural number 5 upto 4 digits which ends with 5 when no digits are repeated.
$$
=(8)(8)(7)(1)+(8)(8)(1)+(8)(1)+(1)=521
$$
Therefore, required number of Natural number
$$
=585+521=1106
$$
Hence, the correct answer is option: 'D'.