Q86 / 200 · JIPMER 2008 · Chemistry

The number of moles of oxygen obtained by the electrolytic decomposition of 108 g water is

  • A
    2.5
  • Correct answer
    B
    3
  • C
    5
  • D
    7.5

Solution

\(\begin{array}{ll} 2 \mathrm{H}_2 \mathrm{O} \xrightarrow{\text { Electrolysis }} 2 \mathrm{H}_2+ &\mathrm{O}_2 \\ 2 \text{mol} & 1 \text{mol} \\ 2 \times 18 =36 g \end{array}\) \(\because 36 \mathrm{~g}\) of \(\mathrm{H}_2 \mathrm{O}\) produce 1 mole of oxygen \(\therefore 108 \mathrm{~g}\) of water will produce oxygen \(=\frac{108}{36}=3 \mathrm{~mol}\)

Hence, the correct answer is option: 'B'.

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