Q87 / 200 · JIPMER 2008 · Chemistry

The change in entropy for the fusion of 1 mole of ice is [mp of ice \(=273 \mathrm{~K}\), molar enthalpy of fusion for ice \(=6.0 \mathrm{~kJ} \mathrm{~mol}^{-1}\) ]

  • A
    \(11.73 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}\)
  • B
    \(18.84 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}\)
  • Correct answer
    C
    \(21.97 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}\)
  • D
    \(24.47 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}\)

Solution

Entropy change of fusion \(\begin{gathered} \Delta S_f=\frac{\Delta H_f}{T} \\ \Delta H_f=60 \times 10^3 \mathrm{~J}, \mathrm{~mol}^{-1}, T=273 \mathrm{~K} \\ \Delta S_f=\frac{60 \times 10^3}{273} \\ =21.97 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1} \end{gathered}\)

Hence, the correct answer is option: 'C'.

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