The number of moles of methane required to produce \(11 \mathrm{~g} \mathrm{CO}_2(\mathrm{~g})\) after complete combustion is : (Given molar mass of methane in \(\mathrm{g} \mathrm{mol}^{-1}: 16\))

• A

  0.35
• B

  0.5
• C

  0.75
• Correct answer
  D

  0.25

Solution

$\mathrm{C}_{\mathrm{n}} \mathrm{H}_{2 \mathrm{n}+2}+\frac{3 \mathrm{n}+1}{2} \mathrm{O}_2 \longrightarrow \mathrm{nCO}_2+(\mathrm{n}+1) \mathrm{H}_2 \mathrm{O}$

$0.25 \mathrm{~mol~} \mathrm{CH}_4$ gives $0.25 \mathrm{~mole}$ (or $11 \mathrm{gm}$ ) $\mathrm{CO}_2$

Hence, the correct answer is option: 'D'.