Q10 / 75 · JEE Main 2026 (21 January Shift 1) · Chemistry
14.0 g of calcium metal is allowed to react with excess HCl at 1.0 atm pressure and 273 K. Which of the following statements is incorrect?
[Given : Molar mass in $\mathrm{g} \mathrm{mol}^{-1}$ of $\mathrm{Ca}-40, \mathrm{Cl}-35.5, \mathrm{H}-1$]
[Given : Molar mass in $\mathrm{g} \mathrm{mol}^{-1}$ of $\mathrm{Ca}-40, \mathrm{Cl}-35.5, \mathrm{H}-1$]
- A0.35 mol of $\mathrm{H}_{2}$ gas is evolved.
- B7.84 L of $\mathrm{H}_{2}$ gas is evolved.
- CThe limiting reagent is calcium metal.
- Correct answerD33.3 g of $\mathrm{CaCl}_{2}$ is produced.
Solution
Reaction: $Ca + 2HCl \rightarrow CaCl_2 + H_2$
Moles of Ca = $\frac{14.0}{40} = 0.35$ mol. Since HCl is in excess, Ca is limiting.
Option (1): $H_2$ evolved = 0.35 mol
Option (2): Volume of $H_2$ at STP = $0.35 \times 22.4 = 7.84$ L
Option (3): Ca is limiting reagent
Option (4): Mass of $CaCl_2 = 0.35 \times 111 = 38.85$ g, not 33.3 g
Statement (4) is incorrect.
Moles of Ca = $\frac{14.0}{40} = 0.35$ mol. Since HCl is in excess, Ca is limiting.
Option (1): $H_2$ evolved = 0.35 mol
Option (2): Volume of $H_2$ at STP = $0.35 \times 22.4 = 7.84$ L
Option (3): Ca is limiting reagent
Option (4): Mass of $CaCl_2 = 0.35 \times 111 = 38.85$ g, not 33.3 g
Statement (4) is incorrect.
Hence, the correct answer is option: 'D'.