Q5 / 160 · TS EAMCET 2024 (10 May Shift 2) · Chemistry
The number of lone pairs of electrons on central atom of $\mathrm{CFF}_3, \mathrm{NF}_3, \mathrm{SF}_4, \mathrm{XeF}_4$ respectively are
- A$0,1,0,2$
- B$2, 1, 0, 0$
- Correct answerC$2, 1, 1, 2$
- D$2,1,1,0$
Solution
$\begin{array}{|c|c|c|c|}\hline \text{Compound} & \begin{array}{c} \text{Valence electron} \\ \text{of central metal atom} \end{array} & \text{Bond pair} & \text{Lone pair} \\ \hline \mathrm{CF}_3 & 7 & 3 & 2 \\ \hline \mathrm{NF}_3 & 5 & 3 & 1 \\ \hline \mathrm{SF}_4 & 6 & 4 & 1 \\ \hline \mathrm{XeF}_4 & 8 & 4 & 2 \\ \hline\end{array}$
$\therefore$ So ' c ' is the correct option.
$\therefore$ So ' c ' is the correct option.
Hence, the correct answer is option: 'C'.