The number of common tangents to the circles x^2+y^2+2x+8y-23=0 and x^2+y^2-4x-10y+9=0, are

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MARKS Content Team · Accepted Answer

Correct answer: 2. The centres and radii of given circles are C_1-1, -4, C_2(2, 5) and r_1=√(1+16+23)=√40, r_2=√(4+25-9)=√20 Now, C_1C_2=√(2+1^2+5+4^2)=√90 And r_1+r_2=√40+√20 Here, C_1C_2<r_1+r_2 ∴ Two common tangents can be drawn

The number of common tangents to the circles $x^{2} + y^{2} + 2 x + 8 y - 23 = 0$ and $x^{2} + y^{2} - 4 x - 10 y + 9 = 0$ , are

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More Circle Questions

The number of common tangents to the circles x2+y2+2x+8y-23=0 and x2+y2-4x-10y+9=0, are

Solution

More Circle Questions

The number of common tangents to the circles $x^{2} + y^{2} + 2 x + 8 y - 23 = 0$ and $x^{2} + y^{2} - 4 x - 10 y + 9 = 0$ , are