Q34 / 180 · COMEDK 2026 (9 May Shift 2) · Chemistry
The number of bond pairs and lone pairs of electrons in the molecule $\text{IF}_5$ is:
- A$6, 0$
- B$4, 1$
- C$4, 2$
- Correct answerD$5, 1$
Solution
The central atom in $\text{IF}_5$ is Iodine (I).
Number of valence electrons in Iodine = $7$.
Number of Fluorine atoms bonded to Iodine = $5$.
Each Fluorine atom forms a single bond with Iodine, so the number of bond pairs = $5$.
Number of valence electrons used in bonding = $5$.
Remaining valence electrons on Iodine = $7 - 5 = 2$.
Number of lone pairs = $\dfrac{2}{2} = 1$.
Thus, the molecule $\text{IF}_5$ has $5$ bond pairs and $1$ lone pair.
Answer: $5, 1$
Number of valence electrons in Iodine = $7$.
Number of Fluorine atoms bonded to Iodine = $5$.
Each Fluorine atom forms a single bond with Iodine, so the number of bond pairs = $5$.
Number of valence electrons used in bonding = $5$.
Remaining valence electrons on Iodine = $7 - 5 = 2$.
Number of lone pairs = $\dfrac{2}{2} = 1$.
Thus, the molecule $\text{IF}_5$ has $5$ bond pairs and $1$ lone pair.
Answer: $5, 1$
Hence, the correct answer is option: 'D'.