Q108 / 225 · JEE Main 2004 · Mathematics

The normal to the curve $x=a(1+\cos \theta), y=a \sin \theta$ at ' $\theta$ ' always passes through the fixed point

Correct answer
A
$(a, 0)$
B
$(0, a)$
C
$(0,0)$
D
$(a, a)$

Solution

Eliminating $\theta$, we get $(x-a)^2+y^2=a^2$. Hence normal always pass through $(a, 0)$

Hence, the correct answer is option: 'A'.

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