Q53 / 120 · JEE Main 2007 · Mathematics

The normal to a curve at $P(x, y)$ meets the $x$-axis at $G$. If the distance of $G$ from the origin is twice the abscissa of $P$, then the curve is a

  • Correct answer
    A
    ellipse
  • B
    parabola
  • C
    circle
  • D
    pair of straight lines

Solution

Equation of normal is $Y-y=-\frac{d x}{d y}(X-x)$ $\begin{aligned} & \Rightarrow G \equiv\left(x+y \frac{d y}{d x}, 0\right) \\ & \left|x+y \frac{d y}{d x}\right|=|2 x| \\ & \Rightarrow y \frac{d y}{d x}=x \text { or } y \frac{d y}{d x}=-3 x \\ & y d y=x d x \text { or } y d y=-3 x d x \\ & \frac{y^2}{2}=\frac{x^2}{2}+c \text { or } \frac{y^2}{2}=-\frac{3 x^2}{2}+c \\ & x^2-y^2=-2 c \text { or } 3 x^2+y^2=2 c. \end{aligned}$

Hence, the correct answer is option: 'A'.

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