Q114 / 200 · NEET 2005 · Physics

The moment of inertia of a uniform circular disc of radius $R$ and mass $M$ about an axis passing from the edge of the disc and normal to the disc is:

  • A
    $M R^2$
  • B
    $\frac{1}{2} M R^2$
  • Correct answer
    C
    $\frac{3}{2} M R^2$
  • D
    $\frac{7}{2} M R^2$

Solution

M.I. of disc about its normal $=\frac{1}{2} M R^2$ M.I. about its one edge $=M R^2+$ $\frac{M R^2}{2}$ $$ \therefore \quad \text { M.I. }=\frac{3}{2} M R^2 $$

Hence, the correct answer is option: 'C'.

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