The moment of inertia of a hollow cubical box of mass M and side length a, about an axis passing through centres of two opposite faces, is equal to…

Question

The moment of inertia of a hollow cubical box of mass M and side length a, about an axis passing through centres of two opposite faces, is equal to (xMa^2)/18. The value of x is

MARKS Content Team · Accepted Answer

Correct answer: 5. Let m be the mass of each face of the cubical box. I=2×(ma^2)/6+4×(ma^2)/12+ma2^2 =(5ma^2)/3 But, m=M/6 ∴I=(5Ma^2)/18 ⇒x=5

The moment of inertia of a hollow cubical box of mass $M$ and side length $a$ , about an axis passing through centres of two opposite faces, is equal to $\frac{x M a^{2}}{18}$ . The value of $x$ is

Solution

More Rotational Motion Questions

The moment of inertia of a hollow cubical box of mass M and side length a, about an axis passing through centres of two opposite faces, is equal to xMa218. The value of x is

Solution

More Rotational Motion Questions

The moment of inertia of a hollow cubical box of mass $M$ and side length $a$ , about an axis passing through centres of two opposite faces, is equal to $\frac{x M a^{2}}{18}$ . The value of $x$ is