The maximum number of electrons present in an orbital with $\mathrm{n}=4,\mathrm{l}=3$ is

There are four types of orbitals which present in atoms namely $\mathrm{s}, \mathrm{p}, \mathrm{d} \mathrm{and} \mathrm{f}.$ The orbitals are having their quantum number which represent the maximum number of electrons and their orientation, spin of the electrons. The given values $\mathrm{n}=4, \mathrm{l}=3$ represents the principal and azimuthal quantum number values of $4\mathrm{f}-$subshell which has seven orbitals. In every orbital, maximum number of electrons can be fitted is $2$, one with $+\frac{1}{2}$ clockwise and another with $-\frac{1}{2}$ anti-clockwise spin rotation. Thus, there are two electrons can be present in the given orbital.