Q132 / 200 · NEET 2023 (All India) · Physics

The magnetic energy stored in an inductor of inductance $4 μH$ carrying a current of $2 A$ is:

Correct answer
A
$8 μJ$
B
$4 μJ$
C
$4 mJ$
D
$8 mJ$

Solution

Magnetic energy stored in an inductor is given by,
$U = \frac{1}{2} L i^{2} = \frac{1}{2} \times (4 \times 10^{- 6}) \times 2^{2} = 8 \times 10^{- 6} J = 8 μJ$

Hence, the correct answer is option: 'A'.

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The magnetic energy stored in an inductor of inductance 4 μH carrying a current of 2 A is:

Solution

More Electromagnetic Induction Questions

The magnetic energy stored in an inductor of inductance $4 μH$ carrying a current of $2 A$ is: