Q88 / 160 · TS EAMCET 2006 · Mathematics

The lines represented by the equation $x^2-y^2-x+3 y-2=0$ are :

  • A
    $x+y-1=0, x-y+2=0$
  • B
    $x-y-2=0, x+y+1=0$
  • C
    $x+y+2=0, x-y-1=0$
  • Correct answer
    D
    $x-y+1=0, x+y-2=0$

Solution

The equation of pair of straight lines is $x^2-y^2-x+3 y-2=0$ This equation can be rewritten as $(x-y+1)(x+y-2)=0$ $\therefore$ The equation of lines which are represented by the given equation, are $x-y+1=0 \text { and } x+y-2=0 .$

Hence, the correct answer is option: 'D'.

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