Q53 / 150 · MHT CET 2008 · Mathematics

The line joining the points $6 \overrightarrow{\mathbf{a}}-4 \overrightarrow{\mathbf{b}}+4 \overrightarrow{\mathbf{c}},-4 \overrightarrow{\mathbf{c}}$ and the line joining the points $-\overrightarrow{\mathbf{a}}-2 \overrightarrow{\mathbf{b}}-3 \overrightarrow{\mathbf{c}}, \overrightarrow{\mathbf{a}}+2 \overrightarrow{\mathbf{b}}-5 \overrightarrow{\mathbf{c}}$ intersect at

  • A
    $-4 \overrightarrow{\mathbf{a}}$
  • B
    $4 \overrightarrow{\mathbf{a}}-\overrightarrow{\mathbf{b}}-\overrightarrow{\mathbf{c}}$
  • C
    $4 \overrightarrow{\mathbf{c}}$
  • Correct answer
    D
    None of these

Solution

The equations of the lines joining $6 \overrightarrow{\mathbf{a}}-4 \overrightarrow{\mathbf{b}}+4 \overrightarrow{\mathbf{c}},-4 \overrightarrow{\mathbf{c}} \quad$ and $-\overrightarrow{\mathbf{a}}-2 \overrightarrow{\mathbf{b}}-3 \overrightarrow{\mathbf{c}}, \overrightarrow{\mathbf{a}}+2 \overrightarrow{\mathbf{b}}-5 \overrightarrow{\mathbf{c}}$ are respectively $$ \overrightarrow{\mathbf{r}}=6 \overrightarrow{\mathbf{a}}-4 \overrightarrow{\mathbf{b}}+4 \overrightarrow{\mathbf{c}}+m(-6 \overrightarrow{\mathbf{a}}+4 \overrightarrow{\mathbf{b}}-8 \overrightarrow{\mathbf{c}}) ...(i) $$ and $\overrightarrow{\mathbf{r}}=-\overrightarrow{\mathbf{a}}-2 \overrightarrow{\mathbf{b}}-3 \overrightarrow{\mathbf{c}}+n(2 \overrightarrow{\mathbf{a}}+4 \overrightarrow{\mathbf{b}}-2 \overrightarrow{\mathbf{c}})$ ...(ii) For the point of intersection, the Eqs. (i) and (ii) should give the same value of $\overrightarrow{\mathbf{r}}$. Hence equating the coefficients of vectors $\overrightarrow{\mathbf{a}}, \overrightarrow{\mathbf{b}}$ and $\overrightarrow{\mathbf{c}}$ in the two expressions for $\overrightarrow{\mathbf{r}}$, we get $$ \begin{array}{l} 6 m+2 n=7 \\ 2 m-2 n=1 \end{array} $$ and $$ 8 m-2 n=7 $$ On solving Eqs. (iii) and (iv), we get $m=1, n=\frac{1}{2} .$ These values of $m$ and $n$, also satisfy the Eq. (v). $\therefore$ The lines intersect. Putting the value of $m$ in Eq. (i), we get the position vector of the point of intersection as $-4 \overrightarrow{\mathbf{c}}$.

Hence, the correct answer is option: 'D'.

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