Q52 / 150 · MHT CET 2008 · Mathematics
If $\overrightarrow{\mathbf{a}} \cdot \hat{\mathbf{i}}=4$, then $(\overrightarrow{\mathbf{a}} \times \hat{\mathbf{j}}) \cdot(2 \hat{\mathbf{j}}-3 \hat{\mathbf{k}})$ is equal to
- A12
- B2
- C0
- Correct answerD$-12$
Solution
$(\overrightarrow{\mathbf{a}} \times \hat{\mathbf{j}}) \cdot(2 \hat{\mathbf{j}}-3 \hat{\mathbf{k}})=\overrightarrow{\mathbf{a}} \cdot\{\hat{\mathbf{j}} \times(2 \hat{\mathbf{j}}-3 \hat{\mathbf{k}})\}$
$$
\begin{array}{l}
=\overrightarrow{\mathbf{a}} \cdot\{-3(\hat{\mathbf{j}} \times \hat{\mathbf{k}})\} \\
=-3(\overrightarrow{\mathbf{a}} \cdot \hat{\mathbf{i}}) \\
=-12 \quad(\because \overrightarrow{\mathbf{a}} \cdot \hat{\mathbf{i}}=4 \text { given })
\end{array}
$$
Hence, the correct answer is option: 'D'.