The length of the radius of the circle which touches the x -axis at the point 1,0 and passes through the point 2,3 is

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MARKS Content Team · Accepted Answer

Correct answer: (D) 5/3 units. Circle touches the x -axis at 1,0 So, center of circle is 1,k and radius is k. Hence, the equation of circle is: x-1^2+y-k^2=k^2 It passes through the point 2,3 , ⇒1+9-6k+k^2=k^2 ∴k=5/3

The length of the radius of the circle which touches the $x$ -axis at the point $(1, 0)$ and passes through the point $(2, 3)$ is

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