Q71 / 197 · NEET 2009 (Mains) · Chemistry

The ionization constant of ammonium hydroxide is $1.77 \times 10^{-5}$ at $298 \mathrm{~K}$. Hydrolysis constant of ammonium chloride -

  • A
    $5.65 \times 10^{-12}$
  • Correct answer
    B
    $5.65 \times 10^{-10}$
  • C
    $6.50 \times 10^{-12}$
  • D
    $5.65 \times 10^{-13}$

Solution

$\mathrm{K}_{\mathrm{h}}=\frac{\mathrm{K}_{\mathrm{W}}}{\mathrm{K}_{\mathrm{b}}}=\frac{10^{-14}}{1.77 \times 10^{-5}}=5.65 \times 10^{-10}$

Hence, the correct answer is option: 'B'.

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