Q3 / 160 · AP EAMCET 2023 (18 May Shift 2) · Chemistry

The ion with smallest radius among the following is

  • A
    $\mathrm{Ca}^{2+}$
  • B
    $\mathrm{K}^{+}$
  • Correct answer
    C
    $\mathrm{Ti}^{4+}$
  • D
    $\mathrm{Sc}^{3+}$

Solution

All the given species have the elements belonging to the same period and ionic radii decrease in a period from left to right. $\mathrm{Ti}^{4+}$ lies to the right of the other species and would be even more small due to a greater positive charge. Thus, order of radii would be :- $$` \mathrm{K}^{+}>\mathrm{Ca}^{2+}>\mathrm{Sc}^{3+}>\mathrm{Ti}^{4+} $$

Hence, the correct answer is option: 'C'.

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