Q3 / 160 · AP EAMCET 2024 (23 May Shift 1) · Chemistry
Match the following
$\begin{array}{|l|l|l|l|}\hline & \text{List -I} & & \text{List-II} \\ & \text{Symbol of element} & & \text{Group number} \\ \hline \text{A} & \text{Mc} & \text{I} & 16 \\ \hline \text{B} & \text{Lv} & \text{II} & 17 \\ \hline \text{C} & \text{Fl} & \text{III} & 15 \\ \hline \text{D} & \text{Ts} & \text{IV} & 14 \\ \hline\end{array}$
The correct answer is
The correct answer is
- AA-III, B-IV, C-I, D-II
- BA-IV, B-III, C-I, D-II
- Correct answerCA-III, B-I, C-IV, D-II
- DA-II, B-IV, C-I, D-III
Solution
Mc (Moscovium) group 15.
Lv (Livermorium) group 16.
Fl (Flerovium) group 14.
Ts (Tennessine) Group 17
Hence, the correct answer is option: 'C'.