Q3 / 160 · AP EAMCET 2024 (23 May Shift 1) · Chemistry

Match the following $\begin{array}{|l|l|l|l|}\hline & \text{List -I} & & \text{List-II} \\ & \text{Symbol of element} & & \text{Group number} \\ \hline \text{A} & \text{Mc} & \text{I} & 16 \\ \hline \text{B} & \text{Lv} & \text{II} & 17 \\ \hline \text{C} & \text{Fl} & \text{III} & 15 \\ \hline \text{D} & \text{Ts} & \text{IV} & 14 \\ \hline\end{array}$
The correct answer is

  • A
    A-III, B-IV, C-I, D-II
  • B
    A-IV, B-III, C-I, D-II
  • Correct answer
    C
    A-III, B-I, C-IV, D-II
  • D
    A-II, B-IV, C-I, D-III

Solution

Mc (Moscovium) group 15. Lv (Livermorium) group 16. Fl (Flerovium) group 14. Ts (Tennessine) Group 17

Hence, the correct answer is option: 'C'.

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