The hybridization of atomic orbitals of nitrogen in ${\mathrm{NO}}_2^{+},\mathrm{ }{\mathrm{NO}}_3^{-}$ and ${\mathrm{NH}}_4^{+}$ respectively are

• A

  $\mathrm{sp}, {\mathrm{sp}}^2\mathrm{ }\mathrm{and} {\mathrm{sp}}^2$
• B

  ${\mathrm{sp}}^2, {\mathrm{sp}}^3\mathrm{ }\mathrm{and} \mathrm{sp}$
• Correct answer
  C

  $\mathrm{sp}, {\mathrm{sp}}^2\mathrm{ }\mathrm{and} {\mathrm{sp}}^3$
• D

  ${\mathrm{sp}}^2, \mathrm{sp}\mathrm{ }\mathrm{and} {\mathrm{sp}}^3$

Hence, the correct answer is option: 'C'.