Q13 / 150 · MHT CET 2011 · Chemistry
The heat of neutralisation of a strong acid and a strong alkali is $57.0 \mathrm{~kJ} \mathrm{~mol}^{-1}$. The heat released
when $0.5$ mole of $\mathrm{HNO}_{3}$ solution is mixed with $0.2$ mole of $\mathrm{KOH}$ is
- A$57.0 \mathrm{~kJ}$
- Correct answerB$11.4 \mathrm{~kJ}$
- C$28.5 \mathrm{~kJ}$
- D$34.9 \mathrm{~kJ}$
Solution
$\because 0.2$ mole will neutralise $0.2$ mole of $\mathrm{HNO}_{3}$.
$$
\begin{aligned}
\therefore \text { Heat evolved } &=57 \times 0.2 \\
&=11.4 \mathrm{~kJ}
\end{aligned}
$$
Hence, the correct answer is option: 'B'.