Q72 / 90 · JEE Main 2012 (07 May Online) · Physics

The graph of an object's motion (along the $x-$ axis) is shown in the figure. The instantaneous velocity of the object at points $A$ and $B$ are $v_A$ and $v_B$ respectively. Then Figure

  • Correct answer
    A
    $v_A=v_B=0.5 \mathrm{~m} / \mathrm{s}$
  • B
    $v_A=0.5 \mathrm{~m} / \mathrm{s} < v_B$
  • C
    $v_A=0.5 \mathrm{~m} / \mathrm{s}>v_B$
  • D
    $v_A=v_B=2 \mathrm{~m} / \mathrm{s}$

Solution

Instantaneous velocity $v=\frac{\Delta x}{\Delta t}$ From graph, $v_A=\frac{\Delta x_A}{\Delta t_A}=\frac{4 m}{8 s}=0.5 \mathrm{~m} / \mathrm{s}$ and $v_B=\frac{\Delta x_B}{\Delta t_B}=\frac{8 m}{16 s}=0.5 \mathrm{~m} / \mathrm{s}$ i.e., $v_A=v_B=0.5 \mathrm{~m} / \mathrm{s}$

Hence, the correct answer is option: 'A'.

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