Q183 / 225 · JEE Main 2005 · Physics

The function $\sin ^2(\omega t)$ represents

  • A
    a periodic, but not simple harmonic motion with a period $2 \pi / \omega$
  • B
    a periodic, but not simple harmonic motion with a period $\pi / \omega$
  • C
    a simple harmonic motion with a period $2 \pi / \omega$
  • Correct answer
    D
    a simple harmonic motion with a period $\pi / \omega$

Solution

$y=\frac{(1-\cos 2 \omega t)}{2}$

Hence, the correct answer is option: 'D'.

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