Q97 / 160 · WBJEE 2010 · Mathematics

The function $\mathrm{f}(\mathrm{x})=\sec \left[\log \left(\mathrm{x}+\sqrt{1+\mathrm{x}^2}\right)\right]$ is

  • A
    odd
  • Correct answer
    B
    even
  • C
    neither odd nor even
  • D
    constant

Solution

Hints : $\mathrm{f}(\mathrm{x})=\sec \left(\ell \ln \left(\mathrm{x}+\sqrt{1+\mathrm{x}^2}\right)\right)=\sec ($ odd function $)=$ even function $\because$ sec is an even function

Hence, the correct answer is option: 'B'.

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