Q139 / 180 · AIIMS 2013 · Physics

The frequency of a light wave in a material is $2 \times 10^{14} \mathrm{~Hz}$ and wavelength is $5000 Å$. The refractive index of material will be

  • A
    $1.50$
  • Correct answer
    B
    $3.00$
  • C
    $1.33$
  • D
    $1.40$

Solution

Using, $\mu=\frac{\mathcal{C}}{v}$ Here, $c=3 \times 10^8 \mathrm{~m} \mathrm{~s}^{-1}$ $v=v \lambda=2 \times 10^{14} \mathrm{~Hz} \times 5000 \times 10^{-10} \mathrm{~m}$ $=1 \times 10^8 \mathrm{~m} \mathrm{~s}^{-1}$ $\therefore \quad \mu=\frac{3 \times 10^8 \mathrm{~m} \mathrm{~s}^{-1}}{1 \times 10^8 \mathrm{~m} \mathrm{~s}^{-1}}=3$

Hence, the correct answer is option: 'B'.

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