Q135 / 180 · AIIMS 2008 · Physics
A converging lens forms a real image \(I\) of an object on its principal axis. A rectangular slab of refractive index \(\mu\) and thickness \(x\) is introduced between \(I\) and the lens, \(I\) will move
- Atowards the lens \((\mu-1) x\)
- Btowards the lens by \(\left(1-\frac{1}{\mu}\right) x\)
- Caway from the lens by \((\mu-1) x\)
- Correct answerDaway from the lens by \(\left(1-\frac{1}{\mu}\right) x\).
Solution
Due to insertion of slab, the optical path increases by $x / \mu$, where $x$ is thickness of slab. Therefore the converging point will shift away by
$\left[x-\frac{x}{\mu}\right]=x\left(1-\frac{1}{\mu}\right)$.
Hence, the correct answer is option: 'D'.