Q135 / 180 · AIIMS 2008 · Physics

A converging lens forms a real image \(I\) of an object on its principal axis. A rectangular slab of refractive index \(\mu\) and thickness \(x\) is introduced between \(I\) and the lens, \(I\) will move

  • A
    towards the lens \((\mu-1) x\)
  • B
    towards the lens by \(\left(1-\frac{1}{\mu}\right) x\)
  • C
    away from the lens by \((\mu-1) x\)
  • Correct answer
    D
    away from the lens by \(\left(1-\frac{1}{\mu}\right) x\).

Solution

Due to insertion of slab, the optical path increases by $x / \mu$, where $x$ is thickness of slab. Therefore the converging point will shift away by $\left[x-\frac{x}{\mu}\right]=x\left(1-\frac{1}{\mu}\right)$.

Hence, the correct answer is option: 'D'.

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