Q29 / 120 · VITEEE 2011 · Chemistry
The freezing point of a solution composed of $10.0$ gof $\mathrm{KCl}$ in $100 \mathrm{~g}$ of water is $4.5^{\circ} \mathrm{C}$. Calculate the van't Hoff factor, i for this solution.
- A$2.50$
- Correct answerB$1.8$
- C$1.2$
- D$1.3$
Solution
$$
\begin{array}{l}
\Delta \mathrm{T}_{f}=i K_{f} m \\
m=\frac{10 \times 1000}{74.55 \times 100}=1.34 \mathrm{~m} \\
{[\mathrm{Molecular} \mathrm{Mass} \text { of } \mathrm{KCl}=74.55]} \\
\mathrm{i}=\frac{\Delta \mathrm{T}_{f}}{\mathrm{~K}_{f} \mathrm{~m}}=\frac{4.5^{\circ} \mathrm{C}}{\left(1.86^{\circ} \mathrm{C} / \mathrm{m}\right)(1.34 \mathrm{~m})}=1.8
\end{array}
$$
Hence, the correct answer is option: 'B'.