Q84 / 200 · NEET 2011 (Screening) · Chemistry
The freezing point depression constant for water is $-1.86^{\circ} \mathrm{C} \mathrm{m}^{-1}$. If $5.00 \mathrm{~g} \mathrm{Na} \mathrm{SO}_4$ is dissolved in $45.0 \mathrm{~g} \mathrm{H}_2 \mathrm{O}$, the freezing point is changed by $-3.82^{\circ} \mathrm{C}$. Calculate the van't Hoff factor for $\mathrm{Na}_2 \mathrm{SO}_4$.
- Correct answerA2.63
- B3.11
- C0.381
- D2.05
Solution
$$
\begin{aligned}
\Delta T_f & =i \times K_f \cdot m \\
\text { or } i & =\frac{\Delta T_f \times W_{\text {solvent }}}{K_f \times n_{\text {solute }} \times 1000} \\
& =\frac{3.82 \times 45}{1.86 \times\left(\frac{5}{142}\right) \times 1000} \\
& =2.63
\end{aligned}
$$
Hence, the correct answer is option: 'A'.