The following solutions were prepared by dissolving $10 \mathrm{g}$ of glucose $\left({\mathrm{C}}_6{\mathrm{H}}_{12}{\mathrm{O}}_6\right)$ in $250 \mathrm{mL}$ of water $\left({\mathrm{P}}_1\right),10 \mathrm{g}$ of urea $\left({\mathrm{CH}}_4{\mathrm{N}}_2\mathrm{O}\right)$ in $250 \mathrm{mL}$ of water $\left({\mathrm{P}}_2\right)$ and $10 \mathrm{g}$ of sucrose $\left({\mathrm{C}}_{12}{\mathrm{H}}_{22}{\mathrm{O}}_{11}\right)$ in $250 \mathrm{mL}$ of water $\left({\mathrm{P}}_3\right).$ The right option for the decreasing order of osmotic pressure of these solutions is:

• Correct answer
  A

  ${\mathrm{P}}_2>{\mathrm{P}}_1>{\mathrm{P}}_3$
• B

  ${\mathrm{P}}_1>{\mathrm{P}}_2>{\mathrm{P}}_3$
• C

  ${\mathrm{P}}_2>{\mathrm{P}}_3>{\mathrm{P}}_1$
• D

  ${\mathrm{P}}_3>{\mathrm{P}}_1>{\mathrm{P}}_2$

Hence, the correct answer is option: 'A'.