Q57 / 180 · NEET 2026 (Re-NEET) · Chemistry

The formula of tetraammineaquachloridocobalt(III) chloride is

  • Correct answer
    A
    $[\text{Co(NH}_3)_4(\text{H}_2\text{O})\text{Cl}]\text{Cl}_2$
  • B
    $[\text{Co(NH}_3)_4\text{Cl}_2]\times\text{H}_2\text{O}$
  • C
    $[\text{Co(NH}_3)_4]\text{Cl}_3\times\text{H}_2\text{O}$
  • D
    $[\text{Co(NH}_3)_4(\text{H}_2\text{O})\text{Cl}]\text{Cl}$

Solution

The complex name is tetraammineaquachloridocobalt(III) chloride.

The central metal ion is cobalt(III), which means $\text{Co}$ is in the $+3$ oxidation state.

The ligands inside the coordination sphere are four ammine ($\text{NH}_3$) molecules which are neutral, one aqua ($\text{H}_2\text{O}$) molecule which is neutral, and one chlorido ($\text{Cl}^-$) ion which has a $-1$ charge.

The coordination sphere is $[\text{Co}(\text{NH}_3)_4(\text{H}_2\text{O})\text{Cl}]$.

The charge on the complex ion is calculated as $+3 + 4(0) + 0 + (-1) = +2$.

To balance the $+2$ charge of the complex ion, two chloride ($\text{Cl}^-$) counter ions are required outside the coordination sphere.

Thus, the formula of the complex is $[\text{Co}(\text{NH}_3)_4(\text{H}_2\text{O})\text{Cl}]\text{Cl}_2$.

Answer: $[\text{Co(NH}_3)_4(\text{H}_2\text{O})\text{Cl}]\text{Cl}_2$

Hence, the correct answer is option: 'A'.

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